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Question Number 130092 by Adel last updated on 22/Jan/21
Commented by 0731619177 last updated on 24/Jan/21
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Answered by Dwaipayan Shikari last updated on 22/Jan/21
log(−(22.22+2.22+2+2...)3)1cosx2cosx4cosx8...=sinxx(x=π2)⇒22.2+22.2+2+22...=2π=log((−π2)3)=iπ+3log(π2)
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