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Question Number 13010 by tawa tawa last updated on 10/May/17

Answered by sandy_suhendra last updated on 10/May/17

$$\mathrm{BC}=\sqrt{5^2-{(7-4)}^2}=4\mathrm{cm}$$$$\mathrm{let}{\mathrm{A}}_{\mathrm{ABCD}}=\mathrm{area}\mathrm{of}\mathrm{ABCD}$$$$\mathrm{and}{\mathrm{P}}_{\mathrm{ABCD}}=\mathrm{perimeter}\mathrm{of}\mathrm{ABCD}$$$${\mathrm{A}}_{\mathrm{prism}}={2\mathrm{A}}_{\mathrm{ABCD}}+{\mathrm{P}}_{\mathrm{ABCD}}\times \mathrm{h}$$$$=2\times \frac{4+7}{2}\times 4+(7+4+4+5)\times 12$$$$=44+240=284{\mathrm{cm}}^2$$

Commented by tawa tawa last updated on 10/May/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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