if Z is any boint on the circle ∣Z−1∣=1 prove that arg(Z−1)=2arg(Z)=(2/3)arg(Z^2 −Z)


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Question Number 130186 by mohammad17 last updated on 23/Jan/21

$i f Z i s a n y b o i n t o n t h e c i r c l e ∣ Z - 1 ∣= 1$ $p r o v e t h a t a r g (Z - 1) = 2 a r g (Z) = \frac{2}{3} a r g (Z^{2} - Z)$
Commented by mohammad17 last updated on 23/Jan/21

$? ? ? ? ?$
	Answered by mathmax by abdo last updated on 26/Jan/21

	$this exercise is solved$
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