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Question Number 130285 by Lordose last updated on 23/Jan/21
Answered by Olaf last updated on 24/Jan/21
Ω=∫26∏9k=1(x−k)dxLetu=x−5Ω=∫−3+1(u+4)...(u+1)u(u−1)...(u−4)duΩ=∫−3+1u(u2−1)(u2−4)(u2−9)(u2−16)duΩ=∫−3+1u(u4−5u2+4)(u4−25u2+144)duΩ=∫−3+1u(u8−30u6+273u4−820u2+576)duΩ=[u1010−30u88+273u66−820u44+576u22]−3+1Ω=[u1010−15u84+91u62−205u4+288u2]−3+1Ω=(110−154+912−205+288)−(31010−15384+91362−205.34+288.9)Ω=249720−915320=−665620=−16645
Commented by Lordose last updated on 24/Jan/21
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