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Question Number 130399 by gowsalya last updated on 25/Jan/21
Answered by Dwaipayan Shikari last updated on 25/Jan/21
f(x)=∑∞n=0anxn=a0+a1x+a2x2+a3x3+...f(0)=a0f′(0)=a1f″(0)=2a2f‴(0)=6a3fiv(0)=24a4..fn(0)=n!an⇒fn(0)n!=an⇒fn(0)n!xn=anxn⇒∑∞n=0fn(0)n!xn=∑∞n=0anxn=f(x)
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