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Question Number 130523 by benjo_mathlover last updated on 26/Jan/21

	Answered by TheSupreme last updated on 26/Jan/21
	$P(4,6,2) { ((2x−3y=2)),((7x−3z=10)),((x+y−z=8)) :} [(2,(−3),0),(7,0,(−3)),(1,1,(−1)) ] ((x),(y),(z) )= ((2),((10)),(8) ) n_1 −n_2 +3n_3 −2x=16→x=−8 z=22 y=−6 Q(−8,6,22) P(4,6,2) with sostitution A wrong B wrong C correct D wrong$
	$P (4, 6, 2)$ ${\begin{cases} 2 x - 3 y = 2 \\ 7 x - 3 z = 10 \\ x + y - z = 8 \end{cases}$ $[\begin{matrix} 2 & - 3 & 0 \\ 7 & 0 & - 3 \\ 1 & 1 & - 1 \end{matrix}] (\begin{matrix} x \\ y \\ z \end{matrix}) = (\begin{matrix} 2 \\ 10 \\ 8 \end{matrix})$ $n_{1} - n_{2} + 3 n_{3}$ $- 2 x = 16 \to x = - 8$ $z = 22$ $y = - 6$ $Q (- 8, 6, 22)$ $P (4, 6, 2)$ $w i t h s o s t i t u t i o n$ $A w r o n g$ $B w r o n g$ $C c o r r e c t$ $D w r o n g$
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