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Question Number 130602 by EDWIN88 last updated on 27/Jan/21
Answered by mr W last updated on 27/Jan/21
=numberof4digitnumberswhicharedivisibleby3:1002,1005,...,9999⇒9999−10023+1=3000i.e.thereare3000fivedigitnumbersendingwith6anddivisibleby3.
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