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Question Number 130632 by bramlexs22 last updated on 27/Jan/21

Answered by EDWIN88 last updated on 27/Jan/21

$$\cos 4095°=\cos (360°\times 11+135°)$$$$=-\frac{\sqrt{2}}{2}$$$$then{\sin }^{-1}\left(\cos 4095°\right)=\sin (-\frac{\sqrt{2}}{2})$$$$=-\frac{\pi }{4}$$

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