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Question Number 130818 by Study last updated on 29/Jan/21
if∣z1∣=∣z2∣=∣z3∣=1and∣1z1∣+∣1z2∣+∣1z3∣=1find∣z1+z2+z3∣=?z1,z2,z3∈complexnumber
Answered by TheSupreme last updated on 29/Jan/21
zi=ρieiθiρ1=ρ2=ρ3=11ρ1+1ρ2+1ρ3=13=1impossiblewecanevaluate1z1+1z2+1z3=1e−iθ1+e−iθ2+e−iθ3=1theneiθ1+eiθ2+eiθ3=(eiθ1+eiθ2+eiθ3)∗=1∗=1
Commented by Study last updated on 30/Jan/21
thankssir
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