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Question Number 130853 by Koyoooo last updated on 29/Jan/21

Answered by mathmax by abdo last updated on 29/Jan/21

$$\mathrm{for}\mathrm{x}\in \mathrm{C}\mathrm{no}\mathrm{difference}\sqrt{{\mathrm{x}}^2}={\left(\sqrt{\mathrm{x}}\right)}^2$$$$\mathrm{inside}\mathrm{R}\sqrt{{\mathrm{x}}^2}=\mid \mathrm{x}\mid \mathrm{here}\mathrm{x}\in \mathrm{R}\mathrm{and}{\left(\sqrt{\mathrm{x}}\right)}^2=\mathrm{x}\mathrm{here}\mathrm{x}\in {\mathrm{R}}^{+}$$

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