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Question Number 130854 by mathlove last updated on 29/Jan/21

lim_(x→2) ((x^x ∙x!−4(3x−4)!)/(3x!−6))

limx2xxx!4(3x4)!3x!6

Answered by Dwaipayan Shikari last updated on 29/Jan/21

lim_(x→2) ((x^x (1+logx)x!+x^x x!ψ(x+1)−12(3x−4)!ψ(3x−3))/(3x!ψ(x+1)))  =((4(1+log(2))+4((3/2)−γ)−24((3/2)−γ))/(9−6γ))  =((4log(2)−26+20γ)/(9−6γ))

limx2xx(1+logx)x!+xxx!ψ(x+1)12(3x4)!ψ(3x3)3x!ψ(x+1)=4(1+log(2))+4(32γ)24(32γ)96γ=4log(2)26+20γ96γ

Commented by mathlove last updated on 29/Jan/21

ψ and γ  is any function

ψandγisanyfunction

Commented by Dwaipayan Shikari last updated on 29/Jan/21

((Γ′(x))/(Γ(x)))=ψ(x)  (Digamma function)  ψ(x)=−γ+Σ_(n=0) ^∞ (1/(n+1))−(1/(n+x))  Γ(x)=∫_0 ^∞ t^(x−1) e^(−t) dt=(x−1)!  γ=Eulerian Constant =lim_(n→∞) Σ_(k=1) ^∞ (1/k)−log(n)

Γ(x)Γ(x)=ψ(x)(Digammafunction)ψ(x)=γ+n=01n+11n+xΓ(x)=0tx1etdt=(x1)!γ=EulerianConstant=limnk=11klog(n)

Commented by mathlove last updated on 29/Jan/21

thanks  bro

thanksbro

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