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Question Number 13091 by tawa tawa last updated on 13/May/17

$$\mathrm{A}\mathrm{motor}\mathrm{car}\mathrm{moves}\mathrm{with}\mathrm{a}\mathrm{velocity}\mathrm{of}20\mathrm{m}/\mathrm{s}\mathrm{on}\mathrm{a}\mathrm{rough}\mathrm{horizontal}\mathrm{road}\mathrm{and}$$$$\mathrm{covers}\mathrm{a}\mathrm{displacement}\mathrm{of}50\mathrm{m}.\mathrm{Find}\mathrm{the}\mathrm{coefficient}\mathrm{of}\mathrm{dynamic}\mathrm{friction}\mathrm{between}$$$$\mathrm{the}\mathrm{tyre}\mathrm{and}\mathrm{the}\mathrm{ground}(\mathrm{g}=10\mathrm{m}/{\mathrm{s}}^2).$$

Answered by mrW1 last updated on 14/May/17

$$a=\frac{v^2}{2s}=\frac{{20}^2}{2\times 50}=4m/s^2$$$$ma=\mu mg$$$$\mu =\frac{a}{g}=\frac{4}{10}=0.4$$

Commented by tawa tawa last updated on 14/May/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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