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Question Number 131007 by Study last updated on 31/Jan/21

$$\frac{d}{dx}\left(\mathrm{\infty }\right)=?or{\left(\mathrm{\infty }\right)}^{\prime }=?$$

Answered by Boucatchou last updated on 31/Jan/21

$$\mathrm{\infty }isunknown,sothey{can}^{\prime }tdosuchoperations..$$

Answered by MJS_new last updated on 31/Jan/21

$$x\mathrm{is}\mathrm{the}\mathrm{variable},\mathrm{\infty }\mathrm{is}\mathrm{a}\mathrm{constant}\Rightarrow {\mathrm{\infty }}^{\prime }=0$$

Commented by MJS_new last updated on 31/Jan/21

$$f\left(x\right)=c$$$$\frac{d}{dx}\left[\underset{c\to \mathrm{\infty }}{\lim }c\right]=0$$

Commented by JDamian last updated on 31/Jan/21

$$But\mathrm{\infty }isnotanumber$$

Commented by MJS_new last updated on 31/Jan/21

$$\mathrm{but}\frac{d}{dx}\left[anythingwithout\mathrm{x}\right]=0$$

Commented by Boucatchou last updated on 31/Jan/21

$$Theyknow\overline{\mathbb{R}}=[-\mathrm{\infty };\mathrm{\infty }],so,whereis\frac{d}{dx}\left(\mathrm{\infty }\right)=0?in\mathbb{R}orin\overline{\mathbb{R}}?$$

Commented by MJS_new last updated on 01/Feb/21

$$\frac{d}{dx}\left[termwithoutx\right]=0$$$$\mathrm{if}\mathrm{this}\mathrm{is}\mathrm{not}\mathrm{clear},\mathrm{I}{\mathrm{can}}^{\prime }\mathrm{t}\mathrm{help}$$

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