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Question Number 131012 by mohammad17 last updated on 31/Jan/21

Commented by mohammad17 last updated on 31/Jan/21

help me sir

helpmesir

Answered by mr W last updated on 31/Jan/21

Commented by mohammad17 last updated on 31/Jan/21

can you complete the solution sir

canyoucompletethesolutionsir

Commented by mr W last updated on 31/Jan/21

b=width of gate=1.5m  F_1 =((ρgbH^2 )/2)  F_2 =ρgbHL  the gate begins to open when  F_1 ×(H/3)≥F_2 ×(L/2)  ((ρgbH^2 )/2)×(H/3)≥ρgbHL×(L/2)  ⇒H≥(√3)L=20(√3)≈34.6 cm  ⇒h≥100+34.6=134.6 cm

b=widthofgate=1.5mF1=ρgbH22F2=ρgbHLthegatebeginstoopenwhenF1×H3F2×L2ρgbH22×H3ρgbHL×L2H3L=20334.6cmh100+34.6=134.6cm

Commented by mohammad17 last updated on 31/Jan/21

thank you sir

thankyousir

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