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Question Number 131075 by benjo_mathlover last updated on 01/Feb/21
Ifa−3=−b−4=−c−5=d+6=e+7=a−b−c+d+e+8thena−b−c+d+e=?
Answered by EDWIN88 last updated on 01/Feb/21
a=k+3;b=−4−k;c=−k−5d=k−6;e=k−7⇔(k+3)−(−4−k)−(−k−5)+k−6++k−7+8=k⇔k+3+4+k+k+5+k−13+8=0⇔4k=−7;k=−74
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