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Question Number 131083 by Dwaipayan Shikari last updated on 01/Feb/21

$$1-\frac{1}{5-\frac{16}{13-\frac{81}{25-\frac{256}{41-\frac{625}{61-\frac{1296}{85-\frac{2401}{113-...}}}}}}}=\frac{6}{{\mathit{\pi }}^2}$$

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