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Question Number 131084 by greg_ed last updated on 01/Feb/21

$$\mathrm{let}\mathrm{solve}\mathrm{this}\mathrm{in}\mathbb{R}:$$$$x^4-x^3-4x^2+x+1=0.$$

Answered by liberty last updated on 01/Feb/21

$${\mathrm{x}}_1=2.414$$$${\mathrm{x}}_2=0.618$$$${\mathrm{x}}_3=-0.414$$$${\mathrm{x}}_4=-1.618$$

Answered by MJS_new last updated on 01/Feb/21

$$(x^2+x-1)(x^2-2x-1)=0$$$$x_{1,2}=-\frac{1}{2}\pm \frac{\sqrt{5}}{2}$$$$x_{3,4}=1\pm \sqrt{2}$$

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