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Question Number 131146 by EDWIN88 last updated on 02/Feb/21
Givenf(x)=f(x+6)∀x∈RIf∫−22f(x)dx=−2and∫−24f(x)dx=2findthevalueof∫410f(x)dx.
Commented by EDWIN88 last updated on 02/Feb/21
⇒∫−24f(x)dx=∫−24f(x+6)dx=2∫410f(x)dx=2
Answered by Ar Brandon last updated on 02/Feb/21
Letx−6=u⇒I=∫−24f(u+6)du=∫−24f(u)du=2
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