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Question Number 131320 by mohammad17 last updated on 03/Feb/21

Answered by mr W last updated on 04/Feb/21

$$2:1+1\Rightarrow \frac{1}{36}$$$$3:1+2,2+1\Rightarrow \frac{2}{36}=\frac{1}{18}$$$$4:2+2,3+1,1+3\Rightarrow \frac{3}{36}=\frac{1}{12}$$$$5:2+3,3+2,1+4,4+1\Rightarrow \frac{4}{36}=\frac{1}{9}$$$$6:3+3,2+4,4+2,1+5,5+1\Rightarrow \frac{5}{36}$$$$7:3+4,4+3,2+5,5+2,1+6,6+1\Rightarrow \frac{6}{36}=\frac{1}{6}$$$$8:4+4,3+5,5+3,2+6,6+2\Rightarrow \frac{5}{36}$$$$9:4+5,5+4,3+6,6+3\Rightarrow \frac{4}{36}=\frac{1}{9}$$$$10:5+5,4+6,6+4\Rightarrow \frac{3}{36}=\frac{1}{12}$$$$11:5+6,6+5\Rightarrow \frac{2}{36}=\frac{1}{18}$$$$12:6+6\Rightarrow \frac{1}{36}$$$$$$$$Xp$$$$21/36$$$$31/18$$$$41/12$$$$51/9$$$$65/36$$$$71/6$$$$85/36$$$$91/9$$$$101/12$$$$111/18$$$$121/36$$

Commented by liberty last updated on 11/Feb/21

$$7:(1,6),(6,1),(2,5),(5,2),(3,4),(4,3)\Rightarrow \frac{6}{36}=\frac{1}{6}$$

Commented by mr W last updated on 04/Feb/21

$$yes,thanks!$$

Answered by liberty last updated on 03/Feb/21

$$\overline{)\begin{array}{cccccccccccc}\mathrm{\Sigma }& 2& 3& 4& 5& 6& 7& 8& 9& 10& 11& 12\\ \mathrm{Freq}& 1& 2& 3& 4& 5& 6& 5& 4& 3& 2& 1\\ \mathrm{prob}& \frac{1}{36}& \frac{2}{36}& \frac{3}{36}& \frac{4}{36}& \frac{5}{36}& \frac{6}{36}& \frac{5}{36}& \frac{4}{36}& \frac{3}{36}& \frac{2}{36}& \frac{1}{36}\end{array}}$$$$$$

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