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Question Number 131332 by ZiYangLee last updated on 03/Feb/21
Iff(x)isafunctiondefinedforallrealnumberssuchthatf(2x)=x+f(x)andf(1)=2,findthevalueoff(64).[Ans:65]
Answered by mr W last updated on 03/Feb/21
f(2)=1+f(1)=1+2=3f(4)=2+f(2)=2+3=5f(8)=4+f(4)=4+5=9f(16)=8+f(8)=8+9=17f(32)=16+f(16)=16+17=33f(64)=32+f(32)=32+33=65
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