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Question Number 131343 by physicstutes last updated on 03/Feb/21

$$\mathrm{A}\mathrm{mapping}\mathrm{is}\mathrm{defined}\mathrm{as}G\to S\mathrm{where}(G,\times )\mathrm{and}(S,+),$$$$\mathrm{show}\mathrm{that}\mathrm{the}\mathrm{mapping}f\left(x\right)=\ln x\mathrm{is}\mathrm{an}\mathrm{isomophism}.$$

Answered by mindispower last updated on 04/Feb/21

$$isomlrphismeisbijectionmorphisme$$$$withoutknowingGandSwecansayjust$$$$f\left(1\right)=0$$$$f\left(xy\right)=f\left(x\right)+f\left(y\right)ifx,y>0$$$$$$

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