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Question Number 131443 by rs4089 last updated on 04/Feb/21

Answered by Olaf last updated on 05/Feb/21

$$\frac{xy}{y-x^2}=\frac{r\cos \theta .r\sin \theta }{r\sin \theta -r^2{\cos }^2\theta }$$$$=\frac{\frac{1}{2}r\sin \left(2\theta \right)}{\sin \theta -r{\cos }^2\theta }$$$$\underset{r\to 0}{\lim }\frac{xy}{y-x^2}=0$$

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