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Question Number 131665 by naka3546 last updated on 07/Feb/21
Answered by mr W last updated on 07/Feb/21
Commented by mr W last updated on 07/Feb/21
202+222−(2s)22×20×22=302+262−(2a)22×30×26⇒442−s222=788−2a239...(i)cosα=a2+s2−1022ascosβ=a2+s2−422as=sinα(a2+s2−1002as)2+(a2+s2−162as)2=1(a2+s2−100)2+(a2+s2−16)2=4a2s2a4+s4−116(a2+s2)+5128=0...(ii)from(i):a2=39(s2−442)44+394=39s244+4922putthisinto(ii):(39s244+4922)2+s4−116(39s244+4922+s2)+5128=034574s4−103997s2+2359305=0S=s2=2(103997±515683457)=90or3011483457
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