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Question Number 131827 by Salman_Abir last updated on 09/Feb/21

Answered by liberty last updated on 09/Feb/21

 = ln ∣tan x∣ ]_(π/4) ^(π/3)  = ln ∣tan (π/3)∣−ln ∣tan (π/4)∣   = (1/2)ln (3)

=lntanx]π4π3=lntanπ3lntanπ4=12ln(3)

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