Question and Answers Forum

All Questions      Topic List

Probability and Statistics Questions

Previous in All Question      Next in All Question      

Previous in Probability and Statistics      Next in Probability and Statistics      

Question Number 131828 by Salman_Abir last updated on 09/Feb/21

Answered by liberty last updated on 09/Feb/21

20 = ((6!)/(3!.3!))

$$\mathrm{20}\:=\:\frac{\mathrm{6}!}{\mathrm{3}!.\mathrm{3}!} \\ $$

Commented by Salman_Abir last updated on 09/Feb/21

detail

$$\mathrm{detail} \\ $$

Answered by mr W last updated on 09/Feb/21

we choose three children for three  red shirts:  C_3 ^6 =((6×5×4)/(3×2×1))=20  ⇒answer (A)

$${we}\:{choose}\:{three}\:{children}\:{for}\:{three} \\ $$$${red}\:{shirts}: \\ $$$${C}_{\mathrm{3}} ^{\mathrm{6}} =\frac{\mathrm{6}×\mathrm{5}×\mathrm{4}}{\mathrm{3}×\mathrm{2}×\mathrm{1}}=\mathrm{20} \\ $$$$\Rightarrow{answer}\:\left({A}\right) \\ $$

Commented by mr W last updated on 09/Feb/21

an other way  say if a child receives a red shirt, he  gets the number “1”, otherwise he  gets the number “0”.  (1+x)^6 =Σ_(k=0) ^6 C_k ^6 x^k   the coefficient of x^3  term is the  answer which is C_3 ^6 =20.

$${an}\:{other}\:{way} \\ $$$${say}\:{if}\:{a}\:{child}\:{receives}\:{a}\:{red}\:{shirt},\:{he} \\ $$$${gets}\:{the}\:{number}\:``\mathrm{1}'',\:{otherwise}\:{he} \\ $$$${gets}\:{the}\:{number}\:``\mathrm{0}''. \\ $$$$\left(\mathrm{1}+{x}\right)^{\mathrm{6}} =\underset{{k}=\mathrm{0}} {\overset{\mathrm{6}} {\sum}}{C}_{{k}} ^{\mathrm{6}} {x}^{{k}} \\ $$$${the}\:{coefficient}\:{of}\:{x}^{\mathrm{3}} \:{term}\:{is}\:{the} \\ $$$${answer}\:{which}\:{is}\:{C}_{\mathrm{3}} ^{\mathrm{6}} =\mathrm{20}. \\ $$

Commented by mr W last updated on 09/Feb/21

an other way  to arrange 3 red and 3 green shirts  in 6 positions (with repetition)  ((6!)/(3!3!))=20

$${an}\:{other}\:{way} \\ $$$${to}\:{arrange}\:\mathrm{3}\:{red}\:{and}\:\mathrm{3}\:{green}\:{shirts} \\ $$$${in}\:\mathrm{6}\:{positions}\:\left({with}\:{repetition}\right) \\ $$$$\frac{\mathrm{6}!}{\mathrm{3}!\mathrm{3}!}=\mathrm{20} \\ $$

Commented by malwan last updated on 09/Feb/21

1+6x+15x^2 +20x^3 +15x^4 +6x^5 +x^6   I love you mr W  thank you so much sir

$$\mathrm{1}+\mathrm{6}{x}+\mathrm{15}{x}^{\mathrm{2}} +\mathrm{20}{x}^{\mathrm{3}} +\mathrm{15}{x}^{\mathrm{4}} +\mathrm{6}{x}^{\mathrm{5}} +{x}^{\mathrm{6}} \\ $$$${I}\:{love}\:{you}\:{mr}\:{W} \\ $$$${thank}\:{you}\:{so}\:{much}\:{sir} \\ $$

Commented by mr W last updated on 09/Feb/21

thanks to you too sir!

$${thanks}\:{to}\:{you}\:{too}\:{sir}! \\ $$

Commented by Salman_Abir last updated on 09/Feb/21

thanks

$$\mathrm{thanks} \\ $$$$ \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com