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Question Number 91862 by jagoll last updated on 03/May/20

$${\log }_2\left(x\right)+{\log }_3\left(x\right)=1$$$$x=?$$

Commented by Tony Lin last updated on 03/May/20

$$\frac{lnx}{ln2}+\frac{lnx}{ln3}=1$$$$lnx\left(\frac{ln6}{ln2\times ln3}\right)=1$$$$lnx=\frac{ln2\times ln3}{ln6}$$$$x=e^{\frac{ln2\times ln3}{ln6}}\approx 1.53$$

Commented by jagoll last updated on 03/May/20

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Commented by hmamarques1994@gmail.com last updated on 03/May/20

$$$$$$x=2^{{log}_{6}3}\approx 1,52959$$

Commented by john santu last updated on 03/May/20

$$2^{{\log }_6\left(3\right)}=3^{{\log }_6\left(2\right)}$$

Answered by john santu last updated on 03/May/20

Commented by john santu last updated on 03/May/20

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Commented by john santu last updated on 03/May/20

1.52959232849

Commented by hmamarques1994@gmail.com last updated on 03/May/20

$$G\widehat{enio}!$$

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