very nice ∫ ((cosec^2 x−2019)/(cos^(2019) x)) dx ?


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Question Number 132004 by bramlexs22 last updated on 10/Feb/21

$very nice$ $\int \frac{cosec^{2} x - 2019}{\cos^{2019} x} dx ?$
	Answered by SLVR last updated on 10/Feb/21


	Commented by SLVR last updated on 10/Feb/21


	Answered by SLVR last updated on 10/Feb/21


	Commented by mr W last updated on 10/Feb/21

	$y o u r p e n h a s n o i n k m o r e . . .$
	Commented by bramlexs22 last updated on 10/Feb/21

	$hahahaha . . blind ink$
	Commented by Rasheed.Sindhi last updated on 10/Feb/21

	$H e / S h e h a s u s e d w h i t e i n k!$ $(T h e b a c k g r o u n d i s a l s o w h i t e b y$ $c h a n c e!)$
	Commented by Ar Brandon last updated on 10/Feb/21
	��Hello Sir Rasheed. It's been quite a longtime. Got missing for awhile. I hope you're doing well. Nice to see you once more��
	Commented by Ar Brandon last updated on 10/Feb/21

	$W h i t e i n k o n f o r u m ?! I g u e s s$ ${i t}^{'} s j u s t a b l a n k c o m m e n t .$
	Commented by Ar Brandon last updated on 10/Feb/21


	Commented by Ar Brandon last updated on 10/Feb/21

	$H a h a!$
	Commented by Rasheed.Sindhi last updated on 14/Feb/21

	$T h a n k s f o r m i s s i n g m e A r B r a n d o n!$
	Answered by SLVR last updated on 11/Feb/21

	$S i r i p o s t e d t h e a n s w e r b u t i c o u l d n o t t h e i m a g e l o a d e d . . .$
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