we say that Log(z_1 z_2 )=Log(z_1 )+Log(z_2 ) when: Re(z_1 )≤0 and Re(z


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Question Number 132032 by mohammad17 last updated on 10/Feb/21

$w e s a y t h a t L o g (z_{1} z_{2}) = L o g (z_{1}) + L o g (z_{2})$ $w h e n : R e (z_{1}) ⩽ 0 a n d R e (z_{2}) ⩽ 0$ $p r o v e t h i s ?$
Commented by mohammad17 last updated on 10/Feb/21

$h e l p m e s i r p l e a s e$
Commented by mohammad17 last updated on 10/Feb/21

$s i r$ $l o g (z) \neq L o g (z)$
Commented by yjjyguuh6uhh last updated on 10/Feb/21

$b e l o w$
Commented by yjjyguuh6uhh last updated on 10/Feb/21

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