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Question Number 132064 by I want to learn more last updated on 10/Feb/21

Commented by mr W last updated on 11/Feb/21

$$(m_1+m_2)a=(m_1-m_2)g$$$$a=\frac{m_1-m_2}{m_1+m_2}g$$$$v=\sqrt{2ah}=\sqrt{\frac{2gh(m_1-m_2)}{m_1+m_2}}$$

Commented by I want to learn more last updated on 11/Feb/21

$$\mathrm{Thanks}\mathrm{sir},\mathrm{i}\mathrm{really}\mathrm{areciate}.$$

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