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Question Number 132123 by mohammad17 last updated on 11/Feb/21

Answered by liberty last updated on 11/Feb/21

$$\left(1\right)\mathrm{c}$$$${\int }_{-1}^{0}0.2\mathrm{dy}+\underset{0}{\stackrel{1}{\int }}(0.2+\mathrm{cy})\mathrm{dy}=1$$$${{0.2\mathrm{y}]}_{-1}^0+(0.2\mathrm{y}+\frac{1}{2}{\mathrm{cy}}^2)]}_0^1=1$$$$0.2+0.2+0.5\mathrm{c}=1$$$$0.5\mathrm{c}=0.6\Rightarrow \mathrm{c}=\frac{6}{5}=1.2$$

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