Σ_(n=1) ^∞ ((sin(n))/n^2 )


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Question Number 132162 by Dwaipayan Shikari last updated on 11/Feb/21

$\underset{n = 1}{\sum^{\infty}} \frac{s i n (n)}{n^{2}}$
	Answered by mnjuly1970 last updated on 11/Feb/21

	$\frac{1}{2 i} [{l i}_{2} (e^{i}) - {l i}_{2} (e^{- i})]$
	Commented by Dwaipayan Shikari last updated on 11/Feb/21

	$B u t e x a c t r e s u l t p o s s i b l e s i r ?$
	Commented by mnjuly1970 last updated on 11/Feb/21

	$i w i l l t r y s i r p a y a n$ $Σ \frac{c o s (n)}{n^{2}} i s v e r y s i m p l e .$ $Σ \frac{s i n (n)}{n^{2}} i s a l i t t l e b i t c h a l l a n g i n g$ $f o u r i e r s e r i e s i s u s e f u l . .$
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