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Question Number 132226 by kaivan.ahmadi last updated on 12/Feb/21

lim_(x→0^+ )   xln(sinx)

limx0+xln(sinx)

Answered by Olaf last updated on 12/Feb/21

sinx ∼_0  x  ⇒ lim_(x→0)  xln(sinx) = lim_(x→0)  xlnx = 0

sinx0xlimx0xln(sinx)=limx0xlnx=0

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