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Question Number 13224 by Tinkutara last updated on 16/May/17

Commented by Tinku Tara last updated on 16/May/17

$$\mathrm{Can}\mathrm{u}\mathrm{please}\mathrm{use}\mathrm{a}\mathrm{different}\mathrm{name}$$$$\mathrm{for}\mathrm{your}\mathrm{user}\mathrm{id}.\mathrm{Since}\mathrm{tinku}\mathrm{tara}$$$$\mathrm{is}\mathrm{publisher}\mathrm{name}.$$$$\mathrm{Thank}\mathrm{You}\mathrm{for}\mathrm{ur}\mathrm{cooperation}.$$

Commented by Tinku Tara last updated on 17/May/17

$$\mathrm{To}\mathrm{create}\mathrm{a}\mathrm{new}\mathrm{username}.\mathrm{Reinstall}$$$$\mathrm{this}\mathrm{app}\mathrm{amd}\mathrm{create}\mathrm{a}\mathrm{different}\mathrm{user}\mathrm{id}.$$

Commented by Tinkutara last updated on 17/May/17

$$\mathrm{If}\mathrm{I}\mathrm{reinstall}\mathrm{this}\mathrm{app},\mathrm{then}\mathrm{all}\mathrm{the}$$$$\mathrm{question}\mathrm{ID}\mathrm{data}\mathrm{will}\mathrm{be}\mathrm{lost}.\mathrm{What}\mathrm{is}$$$$\mathrm{the}\mathrm{problem}\mathrm{with}\mathrm{this}\mathrm{username}?$$

Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 16/May/17

$$\alpha +\beta =\pi +\gamma \Rightarrow sin(\alpha +\beta )=sin(\pi +\gamma )=-sin\gamma$$$${sin}^2(\alpha +\beta )={(-sin\gamma )}^2$$$${sin}^2\alpha .{cos}^2\beta +2sin\alpha cos\alpha sin\beta cos\beta +$$$$+{cos}^2\alpha {sin}^2\beta ={sin}^2\gamma$$$${sin}^2\alpha (1-{sin}^2\beta )+{sin}^2\beta (1-{sin}^2\alpha )+$$$$+2sin\alpha cos\alpha sin\beta cos\beta ={sin}^2\gamma \Rightarrow$$$${sin}^2\alpha +{sin}^2\beta -{sin}^2\gamma =2sin\alpha sin\beta (sin\alpha sin\beta -cos\alpha cos\beta )=$$$$=-2sin\alpha sin\beta cos(\alpha +\beta )=$$$$=-2sin\alpha sin\beta cos(\pi +\gamma )=$$$$=2\mathit{s}\mathit{i}\mathit{n}\mathit{\alpha }\mathit{s}\mathit{i}\mathit{n}\mathit{\beta }\mathit{c}\mathit{o}\mathit{s}\mathit{\gamma }\Rightarrow \mathit{\lambda }=2.◼$$$$$$

Commented by Tinkutara last updated on 17/May/17

$$\mathrm{Thanks}\mathrm{a}\mathrm{lot}!$$

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