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Question Number 132257 by Salman_Abir last updated on 12/Feb/21

Answered by bemath last updated on 12/Feb/21

(i)E(0,0,8), C(3,3,0) vector    EC = 3i^� +3j^� −8k^�  ; ∣EC∣=(√(9+9+64)) =(√(82))   H(0,3,8) ,B(3,0,0) vector    HB=3i^� −3j^� −8k^�  ; ∣HB∣ = (√(82))   so ∣EC∣=∣HB∣ but EC ≠ HB   (ii) vector HG =  { ((EF ; AB)),((DC )) :}  (iii) EF+BD+CF=AB+BD+CF=BF

(i)E(0,0,8),C(3,3,0)vectorEC=3i^+3j^8k^;EC∣=9+9+64=82H(0,3,8),B(3,0,0)vectorHB=3i^3j^8k^;HB=82soEC∣=∣HBbutECHB(ii)vectorHG={EF;ABDC(iii)EF+BD+CF=AB+BD+CF=BF

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