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Question Number 132265 by Salman_Abir last updated on 12/Feb/21

Answered by physicstutes last updated on 12/Feb/21

$$\mathrm{m}=4\mathrm{kg},k=100{\mathrm{Nm}}^{-1}$$$$T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{4}{100}}$$$$\Rightarrow T=\frac{4\pi }{25}\mathrm{s}$$$$f=\frac{1}{T}=\frac{25}{4\pi }\mathrm{Hz}$$$$T=\frac{2\pi }{\omega }\Rightarrow \omega =\frac{2\pi }{T}=2\pi .\frac{25}{4\pi }=\frac{25}{2}\mathrm{rad}/\mathrm{s}$$

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