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Question Number 132474 by bemath last updated on 14/Feb/21
maximumvalueoff(x)=4sin(x)+1−cos(x)is
Commented by EDWIN88 last updated on 14/Feb/21
Commented by bemath last updated on 14/Feb/21
approximation
Answered by mr W last updated on 14/Feb/21
df(x)dx=2cosx4sinx+1+sinx=04cos2x4sinx+1=sin2x4(1−sin2x)4sinx+1=sin2x4sin3x+5sin2x−4=01sin3x−54sinx−1=0Δ=(−12)2+(−512)3=3071728>0⇒1sinx=12(9219+43−9219−43)⇒sinx=29219+43−9219−43cosx=±1−sin2xf(x)max=4sinx+1+1−sin2x≈2.663815973
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