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Question Number 13252 by raktim Ghosh last updated on 17/May/17

lim_(x→0) sin x

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}sin}\:\mathrm{x} \\ $$

Answered by Abbas-Nahi last updated on 17/May/17

=x lim_(x→0)  ((sin x)/x)  =0 (1)  ;since(lim_(×→0) ((sin x)/x) =1)  =0

$$={x}\:{li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\:\frac{\mathrm{sin}\:{x}}{{x}} \\ $$$$=\mathrm{0}\:\left(\mathrm{1}\right)\:\:;{since}\left({li}\underset{×\rightarrow\mathrm{0}} {{m}}\frac{\mathrm{sin}\:{x}}{{x}}\:=\mathrm{1}\right) \\ $$$$=\mathrm{0} \\ $$

Commented by mrW1 last updated on 17/May/17

lim_(x→0)  sin x=sin(lim_(x→0) x)=sin  0=0  just like you do with lim_(x→0)  x=0

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\mathrm{sin}\:{x}=\mathrm{sin}\left(\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}{x}\right)=\mathrm{sin}\:\:\mathrm{0}=\mathrm{0} \\ $$$${just}\:{like}\:{you}\:{do}\:{with}\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:{x}=\mathrm{0} \\ $$

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