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Question Number 132550 by liberty last updated on 15/Feb/21

$$\mathrm{If}a=1\mathrm{then}\underset{x\to (a^2-3x+5)}{\lim }\frac{-4x^2+\sqrt{3x+1}}{\sqrt{x^2+8x}+2}=?$$$$\left(\mathrm{a}\right)-1\left(\mathrm{b}\right)-\frac{4}{5}\left(\mathrm{c}\right)-\frac{3}{5}$$$$\left(\mathrm{d}\right)-\frac{2}{5}\left(\mathrm{e}\right)-\frac{1}{5}$$

Commented by MJS_new last updated on 15/Feb/21

$$x\to (a^2-3x+5)???$$

Commented by liberty last updated on 15/Feb/21

$$\mathrm{yes}\mathrm{sir}.\mathrm{i}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{have}\mathrm{the}\mathrm{answer}$$

Commented by MJS_new last updated on 15/Feb/21

$$\mathrm{how}\mathrm{can}\mathrm{we}\mathrm{have}x\to -3x+6\mathrm{other}\mathrm{than}$$$$x=-3x+6\Rightarrow x=\frac{3}{2}?$$$$\mathrm{in}\mathrm{this}\mathrm{case}\mathrm{the}\mathrm{limit}\mathrm{is}\mathrm{trivial}$$

Commented by liberty last updated on 15/Feb/21

$$\mathrm{i}\mathrm{think}\mathrm{this}\mathrm{question}\mathrm{error}\mathrm{sir}$$

Answered by guyyy last updated on 20/Feb/21

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