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Question Number 68660 by aliesam last updated on 14/Sep/19

$$\int e^{x+e^x}dx$$

Commented by aliesam last updated on 14/Sep/19

$$perfect$$

Commented by Prithwish sen last updated on 14/Sep/19

$$\int {\mathrm{e}}^{\mathrm{x}}{\mathrm{e}}^{{\mathrm{e}}^{\mathrm{x}}}\mathrm{dx}\mathrm{put}{\mathrm{e}}^{\mathrm{x}}=\mathrm{t}\Rightarrow {\mathrm{e}}^{\mathrm{x}}\mathrm{dx}=\mathrm{dt}$$$$\int {\mathrm{e}}^{\mathrm{t}}\mathrm{dt}={\mathrm{e}}^{\mathrm{t}}+\mathrm{c}={\mathbf{e}}^{{\mathbf{e}}^{\mathbf{x}}}+\mathbf{c}\mathbf{please}\mathbf{check}$$

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