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Question Number 132785 by liberty last updated on 16/Feb/21

Commented by liberty last updated on 16/Feb/21

 y=ax^4 +bx^3 +cx^2 +dx+e

y=ax4+bx3+cx2+dx+e

Answered by MJS_new last updated on 16/Feb/21

“critical point” means min/max? in this case:  p(x)=ax^4 +bx^3 +cx^2 +dx+e  p′(x)=4ax^3 +3bx^2 +2cx+d  p′′(x)=12ax^2 +6bx+2c  we need 5 equations  (1) p(0)=3 [(0∣3) on curve]  (2) p′(0)=0 [min/max]  (3) p(1)=2 [(1∣2) on curve]  (4) p′′(1)=0 [inflection]  (5) p′(1)=−6 [slope of tangent]  now solve the system for a, b, c, d, e

criticalpointmeansmin/max?inthiscase:p(x)=ax4+bx3+cx2+dx+ep(x)=4ax3+3bx2+2cx+dp(x)=12ax2+6bx+2cweneed5equations(1)p(0)=3[(03)oncurve](2)p(0)=0[min/max](3)p(1)=2[(12)oncurve](4)p(1)=0[inflection](5)p(1)=6[slopeoftangent]nowsolvethesystemfora,b,c,d,e

Commented by liberty last updated on 16/Feb/21

i don′t understand inflectional   tangent

idontunderstandinflectionaltangent

Commented by MJS_new last updated on 16/Feb/21

the tangent is 6x+y=8 ⇔ y=−6x+8  slope is −6  I corrected it

thetangentis6x+y=8y=6x+8slopeis6Icorrectedit

Commented by malwan last updated on 16/Feb/21

I found  e=3 , d=0 , a=9 , b=−22 , c=12

Ifounde=3,d=0,a=9,b=22,c=12

Commented by liberty last updated on 16/Feb/21

thank you

thankyou

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