find the series solution of the ordinary differential equation y^2 +2xy^1 −3y=x^2 −1 y(0)=1 and y^1 (0)=2


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Question Number 132881 by Engr_Jidda last updated on 17/Feb/21

$f i n d t h e s e r i e s s o l u t i o n o f$ $t h e o r d i n a r y d i f f e r e n t i a l e q u a t i o n$ $y^{2} + 2 {x y}^{1} - 3 y = x^{2} - 1$ $y (0) = 1 a n d y^{1} (0) = 2$
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