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Question Number 13305 by prakash jain last updated on 18/May/17
DoessinA=sinBimplysinA2=sinB2?ForexampleA=πandB=−π?
Answered by ajfour last updated on 18/May/17
A=nπ+(−1)nBwhensinA=sinB;sinA2=sin(nπ2+(−1)nB2)forB=−π;A=πwehaven=2sinA2=sin(2π2+(−1)2B2)sinA2=sin(π+B2)≠sinB2.
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