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Question Number 13307 by tawa tawa last updated on 18/May/17

Answered by ajfour last updated on 18/May/17

$$A=\pi RL-\pi rl+2\pi rh$$$$=\pi \left(9cm\right)\left(\frac{12}{5}\times 9cm\right)-\pi \left(4cm\right)\left(\frac{12}{5}\times 4cm\right)+2\pi \left(4cm\right)\left(10cm\right)$$$$=[\pi \left(\frac{12}{5}\right)(81-16)+80\pi ]{cm}^2$$$$=236\pi {cm}^2.$$

Commented by tawa tawa last updated on 18/May/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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