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Question Number 133103 by 777316 last updated on 18/Feb/21

Commented by bemath last updated on 18/Feb/21

If x+y = c then ln x+ln y ≠ ln c   sir

$$\mathrm{If}\:\mathrm{x}+\mathrm{y}\:=\:\mathrm{c}\:\mathrm{then}\:\mathrm{ln}\:\mathrm{x}+\mathrm{ln}\:\mathrm{y}\:\neq\:\mathrm{ln}\:\mathrm{c}\: \\ $$$$\mathrm{sir}\: \\ $$

Commented by malwan last updated on 18/Feb/21

yes  you are right  thank you

$${yes} \\ $$$${you}\:{are}\:{right} \\ $$$${thank}\:{you} \\ $$

Answered by mr W last updated on 19/Feb/21

3^(3x) +3^(4x−1) =((32)/3)  3×3^(3x) +3^(4x) =32  let t=3^x >0 or x=log_3  t=log_a  b  t^4 +3t^3 −32=0  t≈1.8727  ⇒a=3, b=t≈1.8727

$$\mathrm{3}^{\mathrm{3}{x}} +\mathrm{3}^{\mathrm{4}{x}−\mathrm{1}} =\frac{\mathrm{32}}{\mathrm{3}} \\ $$$$\mathrm{3}×\mathrm{3}^{\mathrm{3}{x}} +\mathrm{3}^{\mathrm{4}{x}} =\mathrm{32} \\ $$$${let}\:{t}=\mathrm{3}^{{x}} >\mathrm{0}\:{or}\:{x}=\mathrm{log}_{\mathrm{3}} \:{t}=\mathrm{log}_{{a}} \:{b} \\ $$$${t}^{\mathrm{4}} +\mathrm{3}{t}^{\mathrm{3}} −\mathrm{32}=\mathrm{0} \\ $$$${t}\approx\mathrm{1}.\mathrm{8727} \\ $$$$\Rightarrow{a}=\mathrm{3},\:{b}={t}\approx\mathrm{1}.\mathrm{8727} \\ $$

Commented by otchereabdullai@gmail.com last updated on 19/Feb/21

nice one

$$\mathrm{nice}\:\mathrm{one} \\ $$

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