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Question Number 133446 by aurpeyz last updated on 22/Feb/21

  an object 3cm high is placed 5cm away  from the pole of a concave spherical  mirror of radius of curvature 25cm.  The position and orientaion and size   of the image are  (a)−8.33cm upright and 5cm  (b)5cm upright and 8.33cm  (c)8.33cm upright and 5cm    i got V(image distance)=−8.33cm  upright and size=5cm.  i know that V=−8.33 means the   image is formed at the 8.33cm mark  behind the mirror.    what i am confused about is wheather  the answer is (a) or (c).    pls help

$$ \\ $$$${an}\:{object}\:\mathrm{3}{cm}\:{high}\:{is}\:{placed}\:\mathrm{5}{cm}\:{away} \\ $$$${from}\:{the}\:{pole}\:{of}\:{a}\:{concave}\:{spherical} \\ $$$${mirror}\:{of}\:{radius}\:{of}\:{curvature}\:\mathrm{25}{cm}. \\ $$$${The}\:{position}\:{and}\:{orientaion}\:{and}\:{size}\: \\ $$$${of}\:{the}\:{image}\:{are} \\ $$$$\left({a}\right)−\mathrm{8}.\mathrm{33}{cm}\:{upright}\:{and}\:\mathrm{5}{cm} \\ $$$$\left({b}\right)\mathrm{5}{cm}\:{upright}\:{and}\:\mathrm{8}.\mathrm{33}{cm} \\ $$$$\left({c}\right)\mathrm{8}.\mathrm{33}{cm}\:{upright}\:{and}\:\mathrm{5}{cm} \\ $$$$ \\ $$$${i}\:{got}\:{V}\left({image}\:{distance}\right)=−\mathrm{8}.\mathrm{33}{cm} \\ $$$${upright}\:{and}\:{size}=\mathrm{5}{cm}. \\ $$$${i}\:{know}\:{that}\:{V}=−\mathrm{8}.\mathrm{33}\:{means}\:{the}\: \\ $$$${image}\:{is}\:{formed}\:{at}\:{the}\:\mathrm{8}.\mathrm{33}{cm}\:{mark} \\ $$$${behind}\:{the}\:{mirror}. \\ $$$$ \\ $$$${what}\:{i}\:{am}\:{confused}\:{about}\:{is}\:{wheather} \\ $$$${the}\:{answer}\:{is}\:\left({a}\right)\:{or}\:\left({c}\right). \\ $$$$ \\ $$$$\boldsymbol{{pls}}\:\boldsymbol{{help}} \\ $$

Commented by aurpeyz last updated on 22/Feb/21

pls help me on this

$${pls}\:{help}\:{me}\:{on}\:{this} \\ $$

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