All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 13349 by tawa tawa last updated on 19/May/17
Answered by ajfour last updated on 19/May/17
forx≠2a,wehave24x2+25x−47=−(ax−2)(8x+3)−5324x2+25x−47=−8ax2+(16−3a)x+6−53comparingcoefficientsofx2orxweseea=−3answerisB)−3.
Commented by tawa tawa last updated on 19/May/17
Godblessyousir.
Terms of Service
Privacy Policy
Contact: info@tinkutara.com