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Question Number 133556 by leena12345 last updated on 22/Feb/21

Commented by leena12345 last updated on 23/Feb/21

$$help$$

Answered by bemath last updated on 23/Feb/21

$$\mathrm{V}=\pi \underset{4}{\stackrel{5}{\int }}{(-{\mathrm{x}}^2+9\mathrm{x}-20)}^2\mathrm{dx}$$$$\mathrm{V}=\pi \underset{4}{\stackrel{5}{\int }}({\mathrm{x}}^4+{81\mathrm{x}}^2+400-{18\mathrm{x}}^3+{40\mathrm{x}}^2-360\mathrm{x})\mathrm{dx}$$$$=\pi {[\frac{{\mathrm{x}}^5}{5}+{27\mathrm{x}}^3+400\mathrm{x}-\frac{9}{2}{\mathrm{x}}^4+\frac{40}{3}{\mathrm{x}}^3-{180\mathrm{x}}^2]}_4^5$$$$=\frac{\pi }{30}$$

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