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Question Number 133583 by bemath last updated on 23/Feb/21
limx→0cosx−1+x22−x424x6
Answered by EDWIN88 last updated on 23/Feb/21
limx→01−x22+x424−x6720+R(x6)−1+x22−x424x6=limx→0−x6720+R(x6)x6=−1720
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