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Question Number 133612 by benjo_mathlover last updated on 23/Feb/21

If  { ((x+y+2z=k)),((x+2y+z=k)),((2x+y+z=k)) :} ; k≠ 0  then x^2 +y^2 +z^2  =?

If{x+y+2z=kx+2y+z=k2x+y+z=k;k0thenx2+y2+z2=?

Commented by mr W last updated on 23/Feb/21

x=y=z=(k/4)  x^2 +y^2 +z^2 =((3k^2 )/(16))

x=y=z=k4x2+y2+z2=3k216

Commented by mr W last updated on 23/Feb/21

why should k≠0?

whyshouldk0?

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