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Question Number 68660 by aliesam last updated on 14/Sep/19

∫e^(x+e^x )  dx

$$\int{e}^{{x}+{e}^{{x}} } \:{dx} \\ $$

Commented by aliesam last updated on 14/Sep/19

perfect

$${perfect} \\ $$

Commented by Prithwish sen last updated on 14/Sep/19

∫e^x e^e^x  dx      put e^x =t⇒e^x dx = dt  ∫e^t dt=e^t +c= e^e^x  +c  please check

$$\int\mathrm{e}^{\mathrm{x}} \mathrm{e}^{\mathrm{e}^{\mathrm{x}} } \mathrm{dx}\:\:\:\:\:\:\mathrm{put}\:\mathrm{e}^{\mathrm{x}} =\mathrm{t}\Rightarrow\mathrm{e}^{\mathrm{x}} \mathrm{dx}\:=\:\mathrm{dt} \\ $$$$\int\mathrm{e}^{\mathrm{t}} \mathrm{dt}=\mathrm{e}^{\mathrm{t}} +\mathrm{c}=\:\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{x}}} } +\boldsymbol{\mathrm{c}}\:\:\boldsymbol{\mathrm{please}}\:\boldsymbol{\mathrm{check}} \\ $$

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